Hello
how to open .csproj in xml file through C# code and add a file as a link
I want to add CommonFileInfo.cs in more than one project
for this i want to add "CommonFileInfo.cs" file as a link in project.
So I want to open every .csproj in xml file and add this code.
<Compile Include="..\Projects\CommonFileInfo.cs">
<Link>CommonFileInfo.cs</Link>
</Compile>
How to do this
Thanks in Advance
One way to modify an XML file is to load it into a System.Xml.XmlDocument:
using System.Xml;
...
XmlDocument doc = new XmlDocument();
doc.Load("file.csproj");
...
//Modify "doc"
...
doc.Save("file.csproj");
Now, how do you "modify the document" Well, first you find the node that you want to manipulate and then you chage that node. To find the node you will need a little bit of XPath:
XmlNode nodeItemGroup = doc.SelectSingleNode("//ItemGroup/Compile").ParentNode;
Next, you add your Xml to the node you found:
XmlElement newChild = doc.CreateElement("Compile");
//...Build the content (see example in the online doc for CreateElement(string)
nodeItemGroup.AppendChild(newChild);
Hope this helps.
static void Main(string[] args)
{
XmlDocument doc = new XmlDocument(); doc.Load(@"project.xml");
XmlNamespaceManager mgr = new XmlNamespaceManager(doc.NameTable);
mgr.AddNamespace("x", "http://schemas.microsoft.com/developer/msbuild/2003");
XmlNode firstCompileNode = doc.SelectSingleNode("/x:Project/x:ItemGroup/x:Compile", mgr);
XmlNode itemGroupNode = firstCompileNode.ParentNode;
XmlNode newCompileNode = doc.CreateNode(XmlNodeType.Element, "Compile", string.Empty);
XmlAttribute newCompileNodeAttribute = doc.CreateAttribute("Include");
newCompileNodeAttribute.Value = @"..\Projects\CommonFileInfo.cs"; newCompileNode.Attributes.Append(newCompileNodeAttribute);
XmlNode linkNode = doc.CreateNode(XmlNodeType.Element, "Link", string.Empty);
linkNode.InnerText = "CommonFileInfo.cs";
newCompileNode.AppendChild(linkNode);
itemGroupNode.AppendChild(newCompileNode);
Console.WriteLine(doc.OuterXml);
Console.Write("{0}Press any key to continue...", Environment.NewLine);
Console.ReadKey();
}
)